php7 php_str_to_str warning: assignment makes pointer from integer without a cast

Am Mittwoch, den 08.02.2017, 14:16 +0100 schrieb Nikita Popov:

On Wed, Feb 8, 2017 at 2:02 PM, Torsten Rosenberger <rosenberger@taow
eb.at>
wrote:

Hello

prehistory:
i tried to use php_str_to_str function to replace some character
insteed of use call_user_func with str_replace

in ext/standard/string.c
PHPAPI zend_string *php_str_to_str(char *haystack, size_t length,
char
*needle, size_t needle_len, char *str, size_t str_len);

so i expect a zend_string as result ?
but when i build i got a warning: assignment makes pointer from
integer
without a cast

buf = php_str_to_str(value,strlen(value),"y",1,"J",1);
    ^
buf is: zend_string *buf;
When buf is: int buf; i got no warning.

i found 2 examples which looks like i have done
ext/standard/var.c
win32/sendmail.c

You probably forgot to include the header declaring this function. If
C
does not have the declaration for a function, it assumes that it
returns
int.

thank's
cannot see the wood for the trees

know it works but with 

buf = php_str_to_str(value, value_len, "'", 1, "\x27", 4);
i get a segfault

buf = php_str_to_str(value, value_len, "'", 1, "\x2", 3);
works but not as i like

i want to build a js escape function 

<script type='javascript'></script> should become  <script type=\x27javascript\x27></script>

an so on

BR/Torsten