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Date: Wed, 8 Feb 2017 14:16:29 +0100
Message-ID: <CAF+90c-Q3mE_GYi8JngkcHdmxUGA9N0MPRUmWLHrtQ_zrvrTYw@mail.gmail.com>
To: Torsten Rosenberger <rosenberger@taoweb.at>
Cc: PHP <internals@lists.php.net>
Content-Type: multipart/alternative; boundary=001a114767fa30520a054804acf3
Subject: Re: [PHP-DEV] php7 php_str_to_str warning: assignment makes pointer
 from integer without a cast
From: nikita.ppv@gmail.com (Nikita Popov)

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On Wed, Feb 8, 2017 at 2:02 PM, Torsten Rosenberger <rosenberger@taoweb.at>
wrote:

> Hello
>
> prehistory:
> i tried to use php_str_to_str function to replace some character
> insteed of use call_user_func with str_replace
>
> in ext/standard/string.c
> PHPAPI zend_string *php_str_to_str(char *haystack, size_t length, char
> *needle, size_t needle_len, char *str, size_t str_len);
>
> so i expect a zend_string as result ?
> but when i build i got a warning: assignment makes pointer from integer
> without a cast
>
> buf = php_str_to_str(value,strlen(value),"y",1,"J",1);
>     ^
> buf is: zend_string *buf;
> When buf is: int buf; i got no warning.
>
> i found 2 examples which looks like i have done
> ext/standard/var.c
> win32/sendmail.c
>

You probably forgot to include the header declaring this function. If C
does not have the declaration for a function, it assumes that it returns
int.

Nikita

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