unexpected modification of a variable

Hi,

Is there any way that a variable can be changed within a function without passing it by reference ?

I have a code like that:

function myfunction($var)
{

 <some code>
 print_r($var); => prints $var which is an object
 anotherfunction($var);  // call by value
 print_r($var); => $var has changed

}

I thought that since there's no reference in any way to the variable it cannot be changed in the function. Am I wrong ?

For variables ...

<?php
$variable = 'rock';

function paper() {
global $variable;
$variable = FUNCTION;
}

function sissors() {
$GLOBALS['variable'] = FUNCTION;
}

echo $variable, PHP_EOL;
paper();
echo $variable, PHP_EOL;
sissors();
echo $variable, PHP_EOL;
?>

For objects, $var is always an alias to an object identifier which
points to the same object...

http://docs.php.net/manual/en/language.oop5.references.php

--
Richard Quadling
Twitter : EE : Zend : PHPDoc
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea

Pascal COURTOIS wrote:

Hi,

Is there any way that a variable can be changed within a function without passing it by reference ?

I have a code like that:

function myfunction($var)
{

<some code> print_r($var); => prints $var which is an object anotherfunction($var); // call by value print_r($var); => $var has changed

}

I thought that since there's no reference in any way to the variable it cannot be changed in the function. Am I wrong ?
Maybe the prototype of anotherfunction() receives it by reference.
Another option would be that <some code> sets some global as a reference
to $var, and $var is changed through it.

If you have such problem, you should provide a test case. But it's
probably a bug in your code that will get solved when piecing it.