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Date: Wed, 29 Jun 2011 16:00:42 +0100
Message-ID: <BANLkTikcR+Kyf533e9iHo1mjf6xkgQLCcg@mail.gmail.com>
To: Pascal COURTOIS <Pascal.Courtois@nouvo.com>
Cc: Internals Mailing List <internals@lists.php.net>
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Subject: Re: [PHP-DEV] unexpected modification of a variable
From: rquadling@gmail.com (Richard Quadling)

On 29 June 2011 15:53, Pascal COURTOIS <Pascal.Courtois@nouvo.com> wrote:
> Hi,
>
> Is there any way that a variable can be changed within a function without=
 passing it by reference ?
>
> I have a code like that:
>
> function myfunction($var)
> {
>
> =C2=A0<some code>
> =C2=A0print_r($var); =3D> prints $var which is an object
> =C2=A0anotherfunction($var); =C2=A0// call by value
> =C2=A0print_r($var); =3D> $var has changed
>
> }
>
>
> I thought that since there's no reference in any way to the variable it c=
annot be changed in the function. Am I wrong ?

For variables ...

<?php
$variable =3D 'rock';

function paper() {
	global $variable;
	$variable =3D __FUNCTION__;
}

function sissors() {
	$GLOBALS['variable'] =3D __FUNCTION__;
}

echo $variable, PHP_EOL;
paper();
echo $variable, PHP_EOL;
sissors();
echo $variable, PHP_EOL;
?>

For objects, $var is always an alias to an object identifier which
points to the same object...

http://docs.php.net/manual/en/language.oop5.references.php



--=20
Richard Quadling
Twitter : EE : Zend : PHPDoc
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