protected __call() question

Hello Jochem,

using 'protected' for __call() hides that mechanism from the outside world,
hence the behavior is correct. Just drop protected and it should work as you
expect.

marcus

Sunday, April 4, 2004, 9:49:44 PM, you wrote:

the following code does not do what I expect, I made this test case
after a new version of PHP5 was put on the system I am developing
yesterday and some of my code no longer works:

<?

Class CallMe
{
public function setup()
{
$this->fakeMethod();
}

 protected function __call($method, $params)
 {
     echo 'you called CallMe::'.$method."\n";
 }

}

echo <<< ___THEEND
EXPECTED RESULT:

you called CallMe::fakeMethod

ACTUAL RESULT:

___THEEND;

$obj = new CallMe();
$obj->setup();

?>>

running the script on 'PHP 5.0.0RC2-dev (cli) (built: Apr 4 2004
13:07:13) (DEBUG)' gives me:

<snip> EXPECTED RESULT: ----------------------------------------- you called CallMe::fakeMethod

ACTUAL RESULT:

PHP Fatal error: Call to protected method CallMe::__call() from context
'' in /var/www/santos/test/call.protected.php on line 7

Fatal error: Call to protected method CallMe::__call() from context ''
in /var/www/santos/test/call.protected.php on line 7
</snip>

Have I misunderstood the way PHP5 works?
Or maybe something is broken? does anyone else get an error?
I don't rule out that this could be something specific to the machine I
am on, unfortunately I am limited by knowledge and access in determining
if this is the case.