php5.1: bug or feature?

21 years ago by val khokhlov — view source — reply

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Hello,

 in php5.1 i get default value of omitted parameter only the first time

i call a function, all subsequent calls get the $tname set in the first call
(like static!). in php5.0 $tname is always empty if omitted (as it should be)
php5.1 updated from cvs on 6.02.2005

[code]

function compile($sname, $tname = '') {
if ($tname == '') $tname = preg_replace("!.php$!", ".phb", $sname);
echo " * source file: $sname\n * target file: $tname\n";
....
}
for ($i = 1; $i < $_SERVER['argc']; $i++) {
$sname = $_SERVER['argv'][$i];
compile($sname);
}

[output]

$ ./php test.php *.php

source file: class.php
target file: class.phb

compiled

source file: class1.php
target file: class.phb

compiled

source file: class2.php
target file: class.phb

compiled

--
Best regards,
val mailto:val@vk.kiev.ua

21 years ago by Dmitry Stogov — view source — reply

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This is the bug #30407. I will try to fix it ASAP.

Thanks. Dmitry.

-----Original Message-----
From: val khokhlov [mailto:val@vk.kiev.ua]
Sent: Wednesday, February 09, 2005 22:07
To: internals@lists.php.net
Subject: [PHP-DEV] php5.1: bug or feature?

Hello,
 in php5.1 i get default value of omitted parameter only 
the first time i call a function, all subsequent calls get
the $tname set in the first call (like static!). in php5.0
$tname is always empty if omitted (as it should be)
php5.1 updated from cvs on 6.02.2005

[code]

function compile($sname, $tname = '') {
if ($tname == '') $tname = preg_replace("!.php$!", ".phb", $sname);
echo " * source file: $sname\n * target file: $tname\n";
....
}
for ($i = 1; $i < $_SERVER['argc']; $i++) {
$sname = $_SERVER['argv'][$i];
compile($sname);
}

[output]

$ ./php test.php *.php

source file: class.php

target file: class.phb

compiled

source file: class1.php

target file: class.phb

compiled

source file: class2.php

target file: class.phb

compiled

--
Best regards,
val mailto:val@vk.kiev.ua