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Date: Sun, 18 Jun 2017 12:58:26 +0200
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To: =?utf-8?Q?Bj=C3=B6rn_Larsson?= <bjorn.x.larsson@telia.com>
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Subject: Re: [PHP-DEV] [RFC]Discuss] Syntax for Arrow Functions
From: ilija.tovilo@me.com (Ilija Tovilo)

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	charset=utf-8

The backslash has actually been one of the earlier options if I remember =
correctly.
I definitely prefer the `fn` keyword as it=E2=80=99s only one character =
more but adds a better visual hint to the arrow function.

I=E2=80=99m also not sure why we=E2=80=99d choose a different arrow =
(`=3D=3D>` or `~>`) when the ambiguity is solved through either a the =
backslash or the `fn` keyword.


> On 15 Jun 2017, at 17:00, Bj=C3=B6rn Larsson =
<bjorn.x.larsson@telia.com> wrote:
>=20
> Den 2017-06-15 kl. 15:34, skrev Fleshgrinder:
>=20
>> On 6/15/2017 3:29 PM, Bj=C3=B6rn Larsson wrote:
>>> Seems like the constraints on this feature makes it hard to fly, =
i.e.
>>> 1. Not a hackish implementation
>>> 2. Non ambiguous syntax
>>> 3. Easy to parse & use syntax for the human
>>>=20
>>> HackLang then prioritised 2 & 3 making the end-users happy, but
>>> had to sacrifise a clean implementation. Any clue if this was a one-
>>> time effort once it was done or something with a lot of drawbacks
>>> in terms of maintenance, performance, evolution etc?
>>>=20
>>> r//Bj=C3=B6rn
>>>=20
>> On Reddit someone proposed the following syntax:
>>=20
>>     \() =3D> echo 'Hello, World'
>>=20
>> It is used by Haskell if I remember correctly and should not be
>> ambiguous since `(` is not allowed in names of classes or functions. =
It
>> actually aligns well with functions that are called with a
>> fully-qualified name (e.g. `\printf('')`).
>>=20
>> Not sure if it would still require hacks though.
>>=20
> So applying that one on Sara's example becomes with some
> options for the arrow:
> 8. $someDict->map(\($v) =3D> $v * 2)->filter(\($v) =3D> $v % 3);
> 9. $someDict->map(\($v) =3D=3D> $v * 2)->filter(\($v) =3D=3D> $v % 3);
> 10. $someDict->map(\($v) ~> $v * 2)->filter(\($v) ~> $v % 3);
>=20
> Interesting :)
>=20
> r//Bj=C3=B6rn
>=20
> --=20
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