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In-Reply-To: <20150119125315.GT7486@phcomp.co.uk>
Date: Mon, 19 Jan 2015 14:13:47 +0000
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Message-ID: <EAA43BD2-09F1-47A1-B9F2-2CD7D08EB92D@ajf.me>
References: <53F8A1FF-C809-4DDF-9C6F-6916C3E4F044@ajf.me> <20150119110639.GO7486@phcomp.co.uk> <8A3DA508-E6A3-486C-8A84-839AEC78D0FF@ajf.me> <20150119125315.GT7486@phcomp.co.uk>
To: Alain Williams <addw@phcomp.co.uk>
X-Mailer: Apple Mail (2.1993)
Subject: Re: [PHP-DEV] [RFC] Combined Comparison (Spaceship) Operator
From: ajf@ajf.me (Andrea Faulds)

Hi Alain,

> On 19 Jan 2015, at 12:53, Alain Williams <addw@phcomp.co.uk> wrote:
>=20
> On Mon, Jan 19, 2015 at 12:30:14PM +0000, Andrea Faulds wrote:
>>=20
>>=20
>>> On 19 Jan 2015, at 11:06, Alain Williams <addw@phcomp.co.uk> wrote:
>>>=20
>>> I like it.
>>>=20
>>> The RFC does not say what the precedence is to be. Could I suggest =
that it be
>>> the same as ''=3D=3D !=3D =3D=3D=3D !=3D=3D <>'' - which keeps it =
consistent with Perl.
>>=20
>> It has the same precedence as the other comparison operators, it=E2=80=99=
s non-associative.
>=20
> Sorry to be a persistent pain, but PHP has 2 sets of comparison =
operators with
> different precedence:
>=20
> ''< <=3D > >=3D''
>=20
> ''=3D=3D !=3D =3D=3D=3D !=3D=3D <>''
>=20
> I think that the RFC should clearly state that spaceship joins the 2nd =
set of
> operators in the precedence table. The introduction kind of hints that =
it would
> join the first lot -- but that would be inconsistent with Perl.
>=20
> http://uk1.php.net/manual/en/language.operators.precedence.php

Ah, I get you. I=E2=80=99m making it the same precedence as Perl (same =
as =3D=3D and !=3D), then. I=E2=80=99ve updated the RFC and will update =
the patch.

Thanks.
--
Andrea Faulds
http://ajf.me/