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To: Yasuo Ohgaki <yohgaki@ohgaki.net>
Cc: Rowan Collins <rowan.collins@gmail.com>, "internals@lists.php.net"
	 <internals@lists.php.net>
Date: Sat, 06 Dec 2014 09:26:43 +0000
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Subject: Re: [PHP-DEV] Re: Only variables can be passed by reference
From: pthreads@pthreads.org (Joe Watkins)

On Sat, 2014-12-06 at 12:03 +0900, Yasuo Ohgaki wrote:
> Hi Rowan,
> 
> On Fri, Dec 5, 2014 at 6:12 PM, Rowan Collins <rowan.collins@gmail.com>
> wrote:
> 
> > The author of function f1() presumably designed it to apply some change to
> > $v, rather than executing only for its side effects and return value. If
> > the caller wants to ignore this design, they can, but they are not using
> > the function as it was designed. If they pass a function return straight
> > into it, they have no way of capturing the change to $v which the author
> > intended them to see.
> 
> 
> The value supplied to f1() is return value.
> In languages, there are literal, constant and variable. Return value is
> variable.
> It's better to keep basic rule. IMHO.
> 
> $top = array_pop(f2());
> 
> is better than
> 
> $v = f2();
> $top = array_pop($v);
> 
> Is there anyone who likes latter?
> Are there any other languages behave like PHP?
> 
> Regards,
> 
> --
> Yasuo Ohgaki
> yohgaki@ohgaki.net

A return value that has no references is a temporary variable, you
forgot about temporary variables.

There is a basic, simple rule; temporary variables cannot be used by
reference, which is perfectly logical since there are no references to
temporary variables, that's what makes them temporary.

I don't see the need to change it.

Cheers
Joe