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In-Reply-To: <545910F1.8030904@sugarcrm.com>
Date: Tue, 4 Nov 2014 18:08:15 +0000
Cc: Leigh <leight@gmail.com>,
 Robert Stoll <php@tutteli.ch>,
 PHP Internals <internals@lists.php.net>
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References: <002601cff777$eb923430$c2b69c90$@tutteli.ch> <CAFMT4NqJDcek6itqAUt2iOyHd2icc-tDdWsEjiRYvG1YFcc5cw@mail.gmail.com> <000601cff80a$972e0250$c58a06f0$@tutteli.ch> <5458937F.9020304@sugarcrm.com> <CAPwsocFQHPDFBVtW5FBCGkz_cy-LB0AzJ48qYJ9zxafAh-G1LQ@mail.gmail.com> <545910F1.8030904@sugarcrm.com>
To: Stas Malyshev <smalyshev@sugarcrm.com>
Subject: Re: [PHP-DEV] Types on the right or on the left
From: ajf@ajf.me (Andrea Faulds)


> On 4 Nov 2014, at 17:46, Stas Malyshev <smalyshev@sugarcrm.com> wrote:
>=20
> Hi!
>=20
>>> "public Foo function bar()" would be so much worse than "public =
function
>>> bar() : Foo"
>>=20
>> Because when you grep for "function bar", in future you'd have to =
know
>> the return type too.
>=20
> Sorry, I do not understand - why to grep for "function bar" you'd have
> to know the type? Just grep for "function bar" as you did before.

Because if that function has a return type, e.g.:

    public function Foo bar()

Then you couldn=E2=80=99t grep for =E2=80=9Cfunction bar=E2=80=9D =
because of the Foo.

If we used this syntax instead, which wouldn=E2=80=99t disrupt grep:

    public Foo function bar();

It=E2=80=99d be inconsistent with normal function declarations which =
would have to have Foo after function.

--
Andrea Faulds
http://ajf.me/