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Organization: Parliament Hill Computers Ltd
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Subject: Cannot use const within try block
From: addw@phcomp.co.uk (Alain Williams)

The code below gives me: PHP Parse error:  syntax error, unexpected T_CONST in ...

try {
    const XXX = 12;

    echo "XXX = " . XXX . "\n";

}catch (ErrorException $e) {
    echo "error {$e->getMessage()}\n";
}

It works if I put the 'cost' before/outside the 'try'.

It also works if I replace the const line by:

    define('XXX', 'twelve');

or

    include "testdef.php";

where testdef.php contains:

    const XXX = 12;

I cannot find this behaviour documented.

a) If there is no good reason for this restriction - can it be removed.

or

b) If there is good reason for it can this be documented.

Regards

-- 
Alain Williams
Linux/GNU Consultant - Mail systems, Web sites, Networking, Programmer, IT Lecturer.
+44 (0) 787 668 0256  http://www.phcomp.co.uk/
Parliament Hill Computers Ltd. Registration Information: http://www.phcomp.co.uk/contact.php
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