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Date: Thu, 14 Jul 2011 23:03:27 +0200
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Subject: Re: [PHP-DEV] Re: $arr = array('Hello', 'world'); $arr();
From: rumi.kg@gmail.com (Rune Kaagaard)

Will this work:

    array('foo', 'bar')('arg1', 'arg2')

?

On Wed, Jun 8, 2011 at 3:48 PM, Christian Kaps
<christian.kaps@mohiva.com> wrote:
> On Wed, 8 Jun 2011 15:39:59 +0200, Jordi Boggiano wrote:
>>
>> On Wed, Jun 8, 2011 at 2:46 PM, Felipe Pena <felipensp@gmail.com> wrote:
>>>
>>> class foo {
>>> =A0 public function __construct() {
>>> =A0 =A0 =A0$this->bar =3D function () { return 1; };
>>> =A0 =A0 =A0// $this->bar(); // error
>>> =A0 =A0 =A0$x =3D $this->bar;
>>> =A0 =A0 =A0$x(); // ok
>>>
>>> =A0 =A0 =A0$this->bar =3D array($this, 'baz');
>>> =A0 =A0 =A0// $this->bar(); // error
>>> =A0 =A0 =A0$x =3D $this->bar;
>>> =A0 =A0 =A0$x(); // ok
>>> =A0 }
>>> =A0 public function baz() {
>>> =A0 =A0 =A0echo 'baz';
>>> =A0 =A0}
>>> }
>>
>> What he meant was passing an existing method as a callback if you
>> don't invoke it, i.e. passing "$this->bar" instead of array($this,
>> "bar"). I don't know how hard it'd be to achieve, but it sounds pretty
>> awesome to me.
>>
>> Cheers
>
> Yep, just what I meant.
>
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