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Date: Mon, 14 Mar 2011 21:36:34 +0100
Message-ID: <AANLkTi=gNoCmQK-Kit61=hXp3Pur-_KJ4p8-H_0YdQ-s@mail.gmail.com>
To: Martin Scotta <martinscotta@gmail.com>, internals@lists.php.net
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Subject: Re: [PHP-DEV] preg_replace does not replace all occurrences
From: landeholm@gmail.com (Hannes Landeholm)

What is more likely to be wrong? Your understanding of a specific
regex pattern (which happens to be full of escapes making it
incredibly hard to read) or the implementation of preg_replace?

~Hannes

On 14 March 2011 16:18, Martin Scotta <martinscotta@gmail.com> wrote:
>
> I chose the simplest example to show the preg_replace behavior, there are
> better (and safer) ways to scape slash characters.
> Anyways, *is this the expected preg_replace behavior?*
>
> =A0Martin
>
> <?php
> function test($str) {
> =A0 =A0static $re =3D '/(^|[^\\\\])\'/';
> =A0 =A0static $change =3D '$1\\\'';
>
> =A0 =A0echo $str, PHP_EOL,
> =A0 =A0 =A0 =A0preg_replace($re, $change, $str), PHP_EOL, PHP_EOL;
> }
>
> test("str '' str"); // bug?
> test("str \\'\\' str"); // ok
> test("'str'"); // ok
> test("\'str\'"); // ok
>
> ----
> Expected:
>
> str '' str
> str \'\' str
>
> str \'\' str
> str \'\' str
>
> 'str'
> \'str\'
>
> \'str\'
> \'str\'
>
> ----
> Result:
>
> str '' str
> str \'' str
>
> str \'\' str
> str \'\' str
>
> 'str'
> \'str\'
>
> \'str\'
> \'str\'
>
>
> =A0Martin Scotta