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Date: Tue, 19 Jan 2010 11:20:02 -0500
Message-ID: <68de37341001190820p486b7c31o5689ab5554b8d260@mail.gmail.com>
To: Stanislav Malyshev <stas@zend.com>
Cc: Michael Wallner <mike@php.net>, internals@lists.php.net
Content-Type: text/plain; charset=UTF-8
Subject: Re: [PHP-DEV] Re: function call chaining
From: oorza2k5@gmail.com (Eddie Drapkin)

On Tue, Jan 19, 2010 at 11:05 AM, Stanislav Malyshev <stas@zend.com> wrote:
> The second was next on my list, while the first seems to me kind of exotic -
> why create object only to call one method and immediately drop it? Why this
> method is not static then?


Why would this imply "dropping" the object?

This:
   $foo = (new bar())->someSetter();
Looks a lot better than this
   $foo = new bar();
   $foo->someSetter();

It's more obvious when you have to store your objects somewhere:
   $foo->bar[$somevar] = (new bar())->someSetter();

Any object that returns $this a lot makes for a valid use case and
right now, we're forced to use a factory method hack, which doesn't
always work, especially in the cases where you have a dynamically
named class (and you can depend on inheritence to guarantee your
method, but not the existence of a static factory method).

What arguments are there against this?  Why shouldn't it be allowed?