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References: <84898698-728C-44ED-BF7A-E0E02C111F68@gmail.com>
	 <4ADFB80B.9050207@hexon.cx>
	 <304A7A3B-9E8D-4BA5-8C01-511090D5F236@gmail.com>
Date: Wed, 21 Oct 2009 19:19:13 -0700
Message-ID: <c25f8d340910211919v596d5f91ub01f6ba615192949@mail.gmail.com>
To: internals@lists.php.net
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Subject: Re: [PHP-DEV] bug when using foreach with references?
From: 0xcafefeed@gmail.com (mm w)

Richard, enumerator exhausted, repeat your sub-sequence again you will get =
it
e.g pointer and pointed

Best Regards

On Wed, Oct 21, 2009 at 7:01 PM, Richard K Miller
<richardkmiller@gmail.com> wrote:
> Hi Jill,
>
>>> <?php
>>> $items =3D array('apple', 'banana', 'carrot');
>>> print_r($items);
>>> foreach ($items as &$item) { }
>>
>> $item is now a reference to the last element of $items.
>>>
>>> print_r($items);
>>> foreach ($items as $item) { }
>>
>> And here, the foreach loop writes to $item for each element: thus
>> assiging that value to the last element of $items.
>
> The last element of $items is 'carrot'. Why does it print apple, banana,
> banana?
>
> It sounds like you're saying that $item should be left with the value
> 'carrot', which makes sense, but why would the original array be modified=
?
> (These are empty foreach loops.)
>
>>> print_r($items);
>>> ?>
>>>
>>> // Output:
>>> Array
>>> (
>>> =C2=A0 =C2=A0[0] =3D> apple
>>> =C2=A0 =C2=A0[1] =3D> banana
>>> =C2=A0 =C2=A0[2] =3D> carrot
>>> )
>>> Array
>>> (
>>> =C2=A0 =C2=A0[0] =3D> apple
>>> =C2=A0 =C2=A0[1] =3D> banana
>>> =C2=A0 =C2=A0[2] =3D> carrot
>>> )
>>> Array
>>> (
>>> =C2=A0 =C2=A0[0] =3D> apple
>>> =C2=A0 =C2=A0[1] =3D> banana
>>> =C2=A0 =C2=A0[2] =3D> banana
>>> )
>>>
>>> Two bananas in the last set?! Not what I expected.
>>
>> You can fix your bug by using 'unset($item);' after the second
>> foreach-loop.
>>
>
>
>
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