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In-Reply-To: <4ADFB80B.9050207@hexon.cx>
Date: Wed, 21 Oct 2009 20:01:40 -0600
Cc: internals@lists.php.net
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Message-ID: <304A7A3B-9E8D-4BA5-8C01-511090D5F236@gmail.com>
References: <84898698-728C-44ED-BF7A-E0E02C111F68@gmail.com> <4ADFB80B.9050207@hexon.cx>
To: Jille Timmermans <jille@hexon.cx>
Subject: Re: [PHP-DEV] bug when using foreach with references?
From: richardkmiller@gmail.com (Richard K Miller)

Hi Jill,

>> <?php
>> $items = array('apple', 'banana', 'carrot');
>> print_r($items);
>> foreach ($items as &$item) { }
> $item is now a reference to the last element of $items.
>> print_r($items);
>> foreach ($items as $item) { }
> And here, the foreach loop writes to $item for each element: thus
> assiging that value to the last element of $items.

The last element of $items is 'carrot'. Why does it print apple,  
banana, banana?

It sounds like you're saying that $item should be left with the value  
'carrot', which makes sense, but why would the original array be  
modified? (These are empty foreach loops.)

>> print_r($items);
>> ?>
>>
>> // Output:
>> Array
>> (
>>     [0] => apple
>>     [1] => banana
>>     [2] => carrot
>> )
>> Array
>> (
>>     [0] => apple
>>     [1] => banana
>>     [2] => carrot
>> )
>> Array
>> (
>>     [0] => apple
>>     [1] => banana
>>     [2] => banana
>> )
>>
>> Two bananas in the last set?! Not what I expected.
> You can fix your bug by using 'unset($item);' after the second  
> foreach-loop.
>