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Message-ID: <cd5680a20806162158i646058b8tf5e6a9a8d527d08@mail.gmail.com>
Date: Tue, 17 Jun 2008 08:58:58 +0400
To: "Larry Garfield" <larry@garfieldtech.com>
Cc: internals@lists.php.net
In-Reply-To: <200806162257.24141.larry@garfieldtech.com>
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References: <4856A547.3080801@gmx.net> <4856B752.1040500@gmx.net>
	 <200806162257.24141.larry@garfieldtech.com>
Subject: Re: [PHP-DEV] [PATCH] [RFC] Closures and lambda functions in PHP
From: indeyets@gmail.com ("Alexey Zakhlestin")

On 6/17/08, Larry Garfield <larry@garfieldtech.com> wrote:
>  - I am a little confused about the OOP interaction.  How does a function
>  become a public method of the class?
>
>  class Example {
>   private $a = 2;
>
>   function myMethod($b) {
>     $lambda = function() {
>       lexical $b;
>       return $this->a * $b; // This part I get
>     };
>     return $lambda;
>   }
>  }
>
>  $e = new Example();
>  $lambda = $e->myMethod();
>  $e->$lambda(5);
>
>  That doesn't seem right at all, but that's how I interpret "Essentially,
>
> closures inside methods are added as public methods to the class that
>
> contains the original method."  Can you give an example of what that actually
>  means?


As far as I understand, it means following:

class Example
{
    private $a = 1;

	private function b()
	{
		return 2;
	}

	public function getLambda($param)
	{
		$lambda = function($lparam) {
			lexical $param;

			return $this->a + $this->b() + $param + $lparam;
		}

		return $lambda;
	}
}

$obj = new Example();
$lambda = $obj->getLambda(3);

$result = $lambda(4); // 1+2+3+4 => 10

-- 
Alexey Zakhlestin
http://blog.milkfarmsoft.com/