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Date: Wed, 30 May 2007 15:02:53 -0700 (PDT)
To: internals@lists.php.net
Cc: stefano federici <s_federici@yahoo.com>
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Message-ID: <44409.30896.qm@web32613.mail.mud.yahoo.com>
Subject: theoretical PHP arrays
From: s_federici@yahoo.com (stefano federici)

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Hi,=0AI trying to find a reason why array functions are not allowed to be u=
sed as normal arrays. To clarify, I'm allowed to write=0A=0A$arr =3D array(=
 "maria", "mario", "luigi", "luisa");=0Aecho $arr[1];=0A=0Abut I'm not allo=
wed to write=0A=0Aecho array( "maria", "mario", "luigi", "luisa")[1];=0A=0A=
In PHP documentation I read that "array" is a language construct, not a fun=
ction. So this may be the reason. But I also tried with=0A=0Aecho (explode =
(" ", "maria mario luigi luisa"))[1];=0A=0Aand this doesn't work either (ev=
en if "explode" is a function). Not surprisingly,=0A=0A$arr =3D explode (" =
", "maria mario luigi luisa");=0Aecho $arr[1];=0A=0Adoes work. So, if I can=
 straightforwardly divide by, say, 2 the integer output by a function, why =
shouldn't I be allowed to straightforwardly use the array output by a funct=
ion?=0A=0AThis is not something completely weird that I'm asking. In Visual=
 Basic (that I know mustn't be the most loved programming language for PHP =
users) you can say=0A=0Aprint array( "maria", "mario", "luigi", "luisa")(1)=
=0A=0AMaybe is THIS the reason why it doesn't work in PHP? ;-)=0A=0AThanks =
for your consideration and help=0A=0AStefano=0A=0A=0A=0A =0AStefano Federic=
i=0A-------------------------------------------------=0AUniversit=E0 degli =
Studi di Cagliari=0AFacolt=E0 di Scienze della Formazione=0ADipartimento di=
 Scienze Pedagogiche e Filosofiche=0AVia Is Mirrionis 1, 09123 Cagliari, It=
alia=0A-------------------------------------------------=0ATel: +39 349 818=
 1955 Fax: +39 070 937 1870
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