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Date: Tue, 24 Apr 2007 14:21:44 +0200
To: Ci <ciptok@gmail.com>
Cc: internals@lists.php.net
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Subject: Re: [PHP-DEV] Re: access to variables
From: tijnema@gmail.com ("Tijnema !")

On 4/24/07, Ci <ciptok@gmail.com> wrote:
> I tried to use smth like that:
>
> zval *data = NULL;
>
> zend_hash_find(Z_ARRVAL_P(PG(http_globals)[TRACK_VARS_SERVER]),
>        "DOCUMENT ROOT", sizeof("DOCUMENT ROOT"), &data);
> strcpy(buffer, Z_STRVAL_P(data);
>
> Then I write the buffer to file, but I don't get correct variable.
> I'm working with php-5.2.1.
>
> Am I in a good way to solve my problem?
>
> Regards,
> Ci

Ok, i don't know a lot about the core of PHP, but i do know the C language.

First of all, i don't see you declaring buffer somewhere, i guess you
did it without showing, or that it is in the core. But if it isn't
both, you should do :)
Also note that buffer should be declared as char *buffer to be able to
use the strcpy function on it.

Second, when you're using the strcpy function, you have 2 '(' used,
and only one ')'
I guess this is a type here. (else it would return error on compilation i guess)

Third, the function strcpy also has a return value. It should be
returned to a pointer to the string where it is copied to.
so it would become:
buffer = strcpy(buffer,Z_STRVAL_P(data));

If all above noted is correct, then it is a problem with your
zend_hash_find function, but as i noted already, i don't know a lot of
the PHP core, so i can't help further with it.

Tijnema