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Subject: Re: Reference Notice
From: na@index20.ru (Andrey Nikolaev)

And another situation...

<?php
function &a() {
   if(1==2)
      return new B; //some reference...
    else
      return null; //error, we cant create B
}
$b_instance = a();
?>

And we got Notice...
Notice: Only variable references should be returned by reference in - on line 6

But if we modify code to:

<?php
function &a() {
   $b = null;
   if(1==2)
      return new B;
    else
      return $b;
}
$b_instance = a();
?>

Than all ok, no notices, and i got what i want... but it's a kludge :-/