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To: Lukas Smith <lsmith@php.net>
Date: Tue, 10 May 2005 11:48:56 -0300
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Subject: Re: [PHP] Re: [PHP-DEV] make new return a reference to existent object
From: lpedretti@suserver.com (Leonardo Pedretti)

Yes, the question was pointed in another way, the destructors are not calle=
d=20
until the last reference to an object has been removed, but if you store a=
=20
reference in an array so you lately return a reference to the already loade=
d=20
instance instead of creating an aliasing of that instance, then you get the=
=20
undesirable behavior that the object is never destroyed until the script=20
ends, because there is always a reference in that array and you can not che=
ck=20
when references are removed in any way.
And leaving the array growing while each object that exists in a huge datab=
ase=20
is slowly loaded and never unloaded, is not an option.

Leo

On Tuesday 10 May 2005 11:26, you wrote:
> Leonardo Pedretti wrote:
> > It would not be such a problem to write something that does the same ta=
sk
> > through a static or global function, but unfortunately it is impossible,
> > due to the following: you can build a cache in an array, then in a
> > __new() function you could check if the requested object is already
> > loaded and return a reference. However, if this is the case, objects th=
at
> > enter the cache never leave it because they are still referenced in the
> > array when all other references have gone, so they never destruct, exce=
pt
> > when the array is destroyed at program's end.
>
> PHP5 has destructors ...
>
> regards,
> Lukas

=2D-=20

Leonardo Pedretti
Axon Sistemas
L=EDder de Equipo Proyecto Basalto