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Date: Fri, 07 Feb 2025 17:19:18 -0600
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Subject: Re: [PHP-DEV] [RFC] Pipe Operator (again)
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From: larry@garfieldtech.com ("Larry Garfield")

On Fri, Feb 7, 2025, at 4:54 PM, Rob Landers wrote:

> Put another way, what is the order of operations for this new operator?
>
> For example, what is the output of
>
> $x ? $y |> strlen(=E2=80=A6) : $z
>
> $x + $y |> sqrt(=E2=80=A6) . EOL
>
> Etc.
>
> I noticed this seems to be missing from the RFC. As a new operator, I=20
> think it should be important to specify that.=20
>
> =E2=80=94 Rob

Pipe deliberately binds fairly low, so most other operators will happen =
first.  Including +, ?? and ? :, for which there are tests:

https://github.com/php/php-src/pull/17118/files#diff-81789df7e324801626e=
f4ef8f629cc95dceed4c09073a2b58b70c811bf776904

https://github.com/php/php-src/pull/17118/files#diff-56cbcf85bd7f68fa7a1=
f837eb15dcc536576986f366976f9642ad20867c471fd

https://github.com/php/php-src/pull/17118/files#diff-775c14f54cd1a27719d=
30bfab62024aeb1625bc3f3621fa0e7c16fb1c7957fdd

So in the examples above, the second would add $x and $y first, then squ=
are-root the result.  The first, I think would probably need parens to a=
void being invalid but I'd have to try it to be sure.

--Larry Garfield