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Date: Mon, 13 Dec 2021 12:19:04 +0100
Message-ID: <CABdc3Wqp3MkfrFM2+_7a6uK86m_9_O0BZy7T5nbUP_Q8cM+BBw@mail.gmail.com>
To: Lynn <kjarli@gmail.com>
Cc: Oliver Nybroe <olivernybroe@gmail.com>, PHP internals <internals@lists.php.net>
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Subject: Re: [PHP-DEV] [RFC] !instanceof operator - reaction measuremen
From: michal.brzuchalski@gmail.com (=?UTF-8?Q?Micha=C5=82_Marcin_Brzuchalski?=)

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pon., 13 gru 2021 o 12:10 Lynn <kjarli@gmail.com> napisa=C5=82(a):

> Heya,
>
> While I definitely agree with this, and after more than 10 years of PHP I
> still have the tendency to write `if ($object !instanceof MyClass)` anywa=
y.
> Would it be possible, or would it collide with constants to do the
> following?
> ```
> $object =3D=3D=3D MyClass;
> $object !=3D=3D MyClass;
> ```
> The reason I'm hoping this would be possible, is that I often have brainl=
ag
> trying to write "instanceof" and I either make several typos, or I end up
> with "instance" and it takes me an error message to realize I forgot the
> "of". The "instanceof" is counterintuitive for me compared to operators.
>
> If this isn't possible and `!instanceof` would be adopted, what about the
> following in addition to the proposed example?
> ```
> $object implements MyInterface;
> $object !implements MyInterface;
> $object extends MyClass;
> $object !extends MyClass;
> ```
>

Why not "not" instead? The "!" in front of "i" in "!implements" is almost
not visible which IMO could get easily ignored unintentionally.
Instead constructs like "$foo not implements stdClass" have higher
visibility and are currently a syntax error.

Cheers,
Micha=C5=82 Marcin Brzuchalski

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