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Date: Wed, 30 Dec 2020 16:39:03 +0100
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 Content preview:  On 30.12.20 12:00, Rowan Tommins wrote: > On 30 December 2020
    08:43:33 GMT+00:00, Markus Fischer <markus@fischer.name> wrote: >> What is
    the scalar value for a ScalarEnum if none is explicitly >> defined? > > The
    question has no answer, because the declaration of the enum itself would
   be invalid: > >> If an enumeration is marked as having a scalar equivalent,
    then all cases must have a unique scalar equivalent defined explicitly. >
    > enum Suit: string { > case Hearts; > case Diamonds; > } > > Presumably,
    this would result in an Error being thrown when compiling the declaration.
    [...] 
 
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Subject: Re: [PHP-DEV] [RFC] Enumerations, Round 2
From: markus@fischer.name (Markus Fischer)

On 30.12.20 12:00, Rowan Tommins wrote:
> On 30 December 2020 08:43:33 GMT+00:00, Markus Fischer <markus@fischer.name> wrote:
>> What is the scalar value for a ScalarEnum if none is explicitly
>> defined?
> 
> The question has no answer, because the declaration of the enum itself would be invalid:
> 
>> If an enumeration is marked as having a scalar equivalent, then all cases must have a unique scalar equivalent defined explicitly.
> 
> enum Suit: string {
> case Hearts;
> case Diamonds;
> }
> 
> Presumably, this would result in an Error being thrown when compiling the declaration.

I see.

What's the quickest way (=less code) to have an enum represent it's 
lexical name as the literal values?

So that `… case Foo; case Bar; …` results in `::Foo->value === 'Foo'` etc.?

Is this possible without implementing this manually for all cases?

thanks,
- Markus