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Date: Thu, 3 Sep 2020 13:03:29 -0300
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Cc: PHP internals <internals@lists.php.net>
Content-Type: multipart/alternative; boundary="00000000000070294d05ae6ae5ff"
Subject: Re: [PHP-DEV] Pass source object to clone like __clone($origThis)
From: david.proweb@gmail.com (David Rodrigues)

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It was just an example to avoid modify how clone works, using existing
features. :)

Em qui, 3 de set de 2020 13:00, Sara Golemon <pollita@php.net> escreveu:

> On Thu, Sep 3, 2020 at 10:40 AM David Rodrigues <david.proweb@gmail.com>
> wrote:
>
>> Now I rethinked about what I said. Really, maybe clone is not the best
>> option. So maybe we can just use a method that will clone and will have
>> access to both informations. But I don't know if it solves the original
>> message.
>>
>> public function getUserCopy() {
>>     $userCopy = clone $this;
>>     $this->copies[] = $userCopy;
>>
>>     return $userCopy;
>> }
>>
>>
> If your goal is to track copies, then a static makes much more sense.
>
> class AllKnowing {
>     private static $copies = [];
>
>     public function __construct(...) {
>         self::$copies[] = $this;
>         ....
>     }
>
>     public function __clone() {
>         self::$copies[] = $this;
>    }
> }
>
> -Sara
>

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