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Date: Thu, 3 Sep 2020 11:00:39 -0500
Message-ID: <CAESVnVohQ6cCzriif1e7Px=roehFb4p_==EpXc8BTHK9Xat9KQ@mail.gmail.com>
To: David Rodrigues <david.proweb@gmail.com>
Cc: PHP internals <internals@lists.php.net>
Content-Type: multipart/alternative; boundary="00000000000025d64b05ae6adb77"
Subject: Re: [PHP-DEV] Pass source object to clone like __clone($origThis)
From: pollita@php.net (Sara Golemon)

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On Thu, Sep 3, 2020 at 10:40 AM David Rodrigues <david.proweb@gmail.com>
wrote:

> Now I rethinked about what I said. Really, maybe clone is not the best
> option. So maybe we can just use a method that will clone and will have
> access to both informations. But I don't know if it solves the original
> message.
>
> public function getUserCopy() {
>     $userCopy = clone $this;
>     $this->copies[] = $userCopy;
>
>     return $userCopy;
> }
>
>
If your goal is to track copies, then a static makes much more sense.

class AllKnowing {
    private static $copies = [];

    public function __construct(...) {
        self::$copies[] = $this;
        ....
    }

    public function __clone() {
        self::$copies[] = $this;
   }
}

-Sara

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