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To: "Daniel J Cain Jr." <dan@cain.sh>,  internals@lists.php.net
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Subject: Re: [PHP-DEV] PHP5:  expected __METHOD__ behavior
From: php@hristov.com (Andrey Hristov)

Daniel J Cain Jr. wrote:
> I am by no means an expert with OOP, so if this is a blatantly retarded 
> question please excuse my ignorance.
> 
> Given this code:
> 
> <?php
> class A
> {
>     function foo()
>     {
>         echo __METHOD__;
>     }
> }
> 
> class B
> {
>     function bar()
>     {
>         // blah
>     }
> }
> 
> $instance = B::foo();
> ?>
> 
> output is "A::foo".
> 
> Is this correct?  I would expect (want maybe :) ) to see output as 
> "B::foo".  If you need more information please let me know.
> 
> TIA
> 
> -dan
> 
Hi,
this "constant" like the others is resolved on compile time. Another example is __CLASS__:
php -r 'class a{ function c() {var_dump(__CLASS__);}}class b extends a{};$a=new b();$a->c();'
dumps :
string(1) "a"

__METHOD__ is resolved as __CLASS__.'::'.__FUNCTION__

IMO the current behaviour is the normal since works like the C preprocessor doing 
substitutions before compile (PHP does it while compiling). You can get what you wanted 
with this  :
echo get_class($this).'::'.__FUNCTION__ (when there is an instance of the class) but AFAIK 
in your case with static calls there is no solution.

Cheers,
Andrey